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taylor10

S.E. Tennessee

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Posted: 11/06/09 05:16pm

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A flat table surface is 12 feet long from point a to point b . An object is launched from point a at a 45 degree angle and lands on point b. How high is the object from the surface of the table when it is midway of the table (or six feet from point a)?

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Posted: 11/06/09 05:41pm

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6 feet

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Crowe

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Posted: 11/06/09 07:05pm

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5.1 feet

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Surfingfool

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Posted: 11/06/09 08:47pm

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Never if using Euclidean space in a gravity void location.

Please provide the planet.
If on earth, how far above sea level.
Is the table in a vacuum?
What speed are we traveling and how close to the speed of light are we?

Need more details.

ngc1514

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Posted: 11/06/09 09:30pm

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Maximum altitude will be .91 meters or about 2.98 feet. You will need to toss the object with an initial velocity of 5.96 meters per second and it will take the object .86 seconds to complete the flight.

This assumes no drag coefficient from the atmosphere.

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d3500ram

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Posted: 11/06/09 09:53pm

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...the key factor here is the 45 degree angle because it limits the velocity of the object for it to land at the specified distance of 12 feet. Had the 12' limitation not been adhered to then there could be an infinite number of possibilities. (i.e. the centenary curve of a kid throwing a ball vs a bullet fired in the air... all of which the object could land 12' away from the starting point.)

There must be a direct correlation between initial velocity at point zero for max height at 6 feet away in order for the object to land exactly 12 feet away. Mass should be irrelevant.

* This post was edited 11/07/09 06:38am by d3500ram *

69 AMX

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Posted: 11/07/09 09:48am

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3 feet

ngc1514

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Posted: 11/07/09 12:04pm

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69 AMX wrote:

3 feet

Close enough to my 2.98 feet. Glad we agree.

For those interested, all the formula necessary to work this out can be found at:

http://hyperphysics.phy-astr.gsu.edu/Hbase/traj.html

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